a_time_slip: (content smile)
Janie Taylor ([personal profile] a_time_slip) wrote2009-06-15 02:33 pm
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For Ian

(x² + y² - 1)³ = x²y³
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[identity profile] malcolmeffect.livejournal.com 2009-06-15 09:18 pm (UTC)(link)
[x^2+(9/4)y^2+z^2-1]^3-[(x^2)(z^3)]-[(9/80)(y^2)(z^3)]=0 when -3<x,y,z<3

[identity profile] a-mind-flip.livejournal.com 2009-06-15 10:44 pm (UTC)(link)
(2x² + 2y² + z² - 1)³ - 1/10x²z³-y²z³ = 0

[identity profile] malcolmeffect.livejournal.com 2009-06-16 03:23 am (UTC)(link)
y^6=x^2-x^6

r=(e^(sin&theta))-2cos4&theta+sin^5[(1/24)(2&theta -&pi)]
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