For Ian

[a_time_slip]

(x² + y² - 1)³ = x²y³

Comments

[malcolmeffect.livejournal.com]

[x^2+(9/4)y^2+z^2-1]^3-[(x^2)(z^3)]-[(9/80)(y^2)(z^3)]=0 when -3<x,y,z<3

[a-mind-flip.livejournal.com]

(2x² + 2y² + z² - 1)³ - ¹/₁₀x²z³-y²z³ = 0

[malcolmeffect.livejournal.com]

y^6=x^2-x^6

r=(e^(sin&theta))-2cos4&theta+sin^5[(1/24)(2&theta -&pi)]